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Glenny Posts: > 500

yup very easy. From what i know, all i can make of it is you will have to give a number infront of the molecule, e.g (not real) CO2 + H20 = 6C12H20 there would be a 6 infront of C and a 12 infront of H? i cant remember it all too well, im crap at biology now i look at it...
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Posted: 2006-02-07 22:25:23
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Uncle Bob Posts: 202

Thought I had it - nevermind...

_________________
Brevior saltare cum deformibus mulieribus est vita

[ This Message was edited by: Uncle Bob on 2006-02-07 23:24 ]
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Posted: 2006-02-08 00:23:38
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haynesycop Posts: > 500

So can anyone help i just don't get it at all it is supposed to be pretty easy but i have always been crap at it got to be done by friday


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Posted: 2006-02-08 09:06:49
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methylated_spirit Posts: > 500

Arnold Schwarzenegger destroyed the periodic table, because Arnold Schwarzenegger only recognizes the element of surprise.

(sorry)

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Hello, Scroto!

[ This Message was edited by: methylated_spirit on 2006-02-08 09:36 ]
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Posted: 2006-02-08 10:32:12
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Luke-the-magic-man Posts: > 500

Quote:
On 2006-02-08 10:32:12, methylated_spirit wrote:
Arnold Schwarzenegger destroyed the periodic table, because Arnold Schwarzenegger only recognizes the element of surprise.

(sorry)

_________________
Hello, Scroto!

[ This Message was edited by: methylated_spirit on 2006-02-08 09:36 ]



ha ha, that made me laugh mate.

Il ask my gf if I see her tonight shes on a2 chemistry I think, aka year 13
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Posted: 2006-02-08 19:50:25
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clank Posts: > 500

Ans 1) BaCl2 + Na2SO4 gives 2(NaCl) + BaSO4
2(C5H11OH) + 15(O2) gives 10(CO2) + 12(H2O)

Ans 2) % of K+ ions = (mass of K)/total mass = 78/138 = 56.52%
Similarly % of CO3 ion = 60/138 = 43.48%

moles of AgNO3 = 10/mol. mass of AgNO3 = 10/170 = 0.059

if you balance the eq you'll see one mole of AgNO3 gives 0.5 moles of Ag2CO3 so 0.059 will give 0.029 moles of Ag2CO3 weighing
0.029x276 = 8.0g

to react with 10g ie 0.059 moles of AgNO3 you need 0.029 moles of K2CO3 ie 0.029x138 = 4g

Ans 3) C3H7N2O The solution is slightly understanding based and i dont think i'll be able to explain it in writing so i'm just printing the answer.

Hope that helps
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Posted: 2006-02-09 13:25:09
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haynesycop Posts: > 500

Wow thanks mate that is great! I am just thick were chemistry is concerned!

THANK YOU!!!!!!



If i can ever return the favour then let me know.


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Posted: 2006-02-09 13:49:46
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fatreg Posts: > 500

So...

Miss C,

can you please expalin your working out?

they got me with that everytime at school

fatreg
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Posted: 2006-02-09 14:05:35
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Kwiksta Posts: > 500

oh! we're doing this at the moment in school...ill try 2 help!
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Posted: 2006-02-09 20:35:14
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haynesycop Posts: > 500

Ok so is anybody up for some more questions, the book i use to help me has disappeared from the college library, it is like my chemistry bible, not happy.



I got one question were i have to work out a pka and i was off for that lesson, so totally clueless.
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Posted: 2006-03-08 09:51:40
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