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I don't think he wants the answers, I think he wants to know how to do it.

Its been a long time since I did simultaneous equations but... I'll try to start you off..


3x + 2y - z = 0

so by taking Z to the other side of the equal sign you get

z = 3x + 2y

now you have z expressed in terms of x and y can substitude for y in the 3rd equation

5x - 2(3x + 2y) = 2
which simplifies to
5x - 6x - 4y = 2
or simplified further
-x - 4y = 2

now swap 2 and x to give

-2 - 4y = x

so we can now substitute for x and z into the second equation to determine the value of y

once you have the numerical value of y you can supply that into the first equation (substituting z in terms of x too) and you can derive the numerical value of x leaving a simple task to find the value of Z
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Posted: 2004-10-21 15:04:35
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Just buy a calculator that does simultaneous equations. This message was posted from a T610
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Posted: 2004-10-21 15:08:07
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can you use those in exams these days?
don't you still have to know how to do it by hand?
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Posted: 2004-10-21 15:09:10
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CAN ANYONE HELP ME? Instead of wasting Esato's bandwidth? Please. I am getting restless. :-( This message was posted from a T230
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Posted: 2004-10-21 15:11:40
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@whizzkid, read back a few posts, I have already helped you!!

_________________
...Unless I'm very much mistaken
my K700 review

[ This Message was edited by: masseur on 2004-10-21 14:19 ]
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Posted: 2004-10-21 15:13:36
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He's expecting that someone does it for him...

It's not that dificult whizzkid! Just follow masseur's explanation.
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Posted: 2004-10-21 15:25:00
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Masseur did it right. This message was posted from a Z1010
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Posted: 2004-10-21 15:47:25
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Use a casio fx991 ms, its easy with that. This message was posted from a K700i
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Posted: 2004-10-21 15:48:15
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You can also use the determinants to solve the problem. Any higher math textbooks will tell you. Else if you want fast answers, substitute some values by trial and error. This message was posted from a T630
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Posted: 2004-10-21 16:05:32
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Quote:
On 2004-10-21 16:05:32, plasmadog wrote:
Else if you want fast answers, substitute some values by trial and error.


No way it would be fast...
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Posted: 2004-10-21 16:22:24
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