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This is an easy one I did a couple of weeks ago, so it should be REALLY EASY for you lot!
Solve the equation to find the co-ordinates of
each intersection
x(x-3) = x^2(1-x)
@Kimcheeboi: Damn, I can't do it, you seem to be posting all questions just out of my grasp, haven't covered inductors etc. in physics yet!
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[ This Message was edited by: maddav on 2004-10-21 23:43 ]
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Posted: 2004-10-22 00:41:48
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x=plus or minus sqrrt or 3 or 0
@maddav
fine!
here ya go:
integrate:
x^3/(4x^2+9)^(3/2)
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Posted: 2004-10-22 00:59:00
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almost there Kim, but i said
co-ordinates
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Posted: 2004-10-22 01:01:15
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i wasn't paying attention
btw how are you supposed to find the coordinates of a linear equation? it's not even on a plane!
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[ This Message was edited by: kimcheeboi on 2004-10-22 00:08 ]
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Posted: 2004-10-22 01:07:00
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OK, I'm really tired and I missed out the VERY top part of my notes (the y's), but i think this is what i did (that's re-assuring
)
y=x(x-3)
y=x^2(1-x)
you should end up with what you got
(x)(x^2-3)
therefore y= (x)(x^2-3)
when x =0,
y = 0
when x = +rt3
y= (rt3)(3-3)
y= 3-3rt3 or
3(1-rt3)
and the same for -rt3, i would do it, but I've got to go to bed now.
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[ This Message was edited by: maddav on 2004-10-22 00:34 ]
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Posted: 2004-10-22 01:21:40
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@anyone:
I've got some homework, and i solved this question, but the book says I'm wrong
our teacher said there was a number of mistakes in it as well, so it's really annoying. Anyway, here it is, just the y values please, haven't bothered solving the x values yet.
Simultaneous equations:
x=2y-2
x^2 = y^2 +7
Thanks!
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[ This Message was edited by: maddav on 2004-10-28 18:22 ]
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Posted: 2004-10-28 18:48:31
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x=2
y^2= -3
if u want explanation ask (check my answers with the books and urs)
Explanation:
take
x=2y-2 and square it
x^2=4y^2-2
x^2=y^2+7
rearrange
x^2 - 4y^2=-2
x^2 - y^2=7
subtract
-3y^2=9
divide by -3
y^2=-3
substitue into x^2=y^2+7
x^2= -3 +7
x^2=4
x=2
i'm probably wrong as always but its my offering
50
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[ This Message was edited by: 50Cent on 2004-10-28 18:08 ]
[ This Message was edited by: 50Cent on 2004-10-28 18:15 ]
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Posted: 2004-10-28 19:08:09
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When i was in general school, it was a usually question of math teachers to students: a ship is 55 m long and there are 273 passangers on board. How old is the captain?
This message was posted from a T68i
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Posted: 2004-10-28 19:09:44
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thats a tough one
just gimme a month to find a 55m boat that has a 279 passenger capacity
den i'll just ask the captain
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Posted: 2004-10-28 19:19:07
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@boba:
@50: Ummm, it's a simultaneous equation, with an x^2 and y^2 values, so there should be 2 values for x. This is what i got:
x = 2y-2
x^2 = y^2 + 7
Substitute the value for x, into the second equation:
(2y-2)(2y-2) = y^2 + 7
= 4y^2 -4y -4y +4 = y^2 +7
= 3y^2 - 8y -11 = 0
= (y+1)(3y-11) = 0
y+1=0
y=-1
OR
3y-11=0
y=11/3
3y=11
y=11/3
That's the y values but the book has
y=3 or
-1/3
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Posted: 2004-10-28 19:20:41
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