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we cant probably determine that via ur age. I'm 17 and took the exams earlier this year.
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Posted: 2004-10-28 20:45:37
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I'm 20 and i'm gonna finish four years of college by June 2005. So that means i wrote the 12th exams when i was 16.
_________________
My precious - my K700
[ This Message was edited by: kllr_dude on 2004-10-28 19:52 ]
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Posted: 2004-10-28 20:51:16
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Sounds similar to the GCSE's I took, in which i got an A, but in all fairness, grades on an exam, don't always translate, to good/bad overall competence in a subject.
Just my thoughts!
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Posted: 2004-10-28 21:09:17
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as i have just proved
cant even square terms
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Posted: 2004-10-28 21:11:51
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y=2x + 1
y^2=2x^2 +x
how do i do this
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Posted: 2004-10-29 12:18:10
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x = -1 and x = -1/2
Same technique as above
y=2x+1
y^2=2x^2+x
subst y value in eqn 1 in eqn 2
(2x+1)^2=2x^2+x
=> 2x^2+3x+1=0
=> 2x^2 + 2x + x + 1 = 0
=> (2x + 1) ( x +1 ) = 0
so u get x, subst both values in eqn 1 to get y values
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Posted: 2004-10-29 12:31:08
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Quote:
On 2004-10-29 12:31:08, kllr_dude wrote:
x = -1 and x = -1/2
Same technique as above
y=2x+1
y^2=2x^2+x
subst y value in eqn 1 in eqn 2
(2x+1)^2=2x^2+x
=> 2x^2+3x+1=0
=> 2x^2 + 2x + x + 1 = 0
=> (2x + 1) ( x +1 ) = 0
so u get x, subst both values in eqn 1 to get y values
ah right so
y=(2 x -1) +1
y=-1
and
y=(2 x -1/2)+1
y=0
i think.
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Posted: 2004-10-29 12:42:03
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This so isnt the maths i did at school!
and i went to a grammar school? what went wrong!?
we were all about algebra, but saying that i never did get all the z,y's so maybe i aint got a hope in hell of getting calculus?
fatreg
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Posted: 2004-10-30 15:44:20
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help me with series, peeps!
power, taylor, and maclaurin series!
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Posted: 2004-11-17 01:11:39
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I need help, i just can't work out what to do, I know about half of this problem, and the answer, but I need to know how to finish it, I'm sure it's really simple but I just can't get my head round it, here it is:
I need the gradient for the curve f(x) at point A (2,13)
f(x) = 3x² + 2x¯¹
f¹(x) = 6x - 2x¯²
I'm sure for the gradient, i need to do something like substituting the x co-ordinate value, but then I don't know what to do next:
f¹(2) =
Help me please
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Posted: 2004-11-18 20:57:08
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